\(\int x (c+a^2 c x^2)^3 \arctan (a x)^2 \, dx\) [276]

   Optimal result
   Rubi [A] (verified)
   Mathematica [A] (verified)
   Maple [A] (verified)
   Fricas [A] (verification not implemented)
   Sympy [A] (verification not implemented)
   Maxima [A] (verification not implemented)
   Giac [F]
   Mupad [B] (verification not implemented)

Optimal result

Integrand size = 20, antiderivative size = 200 \[ \int x \left (c+a^2 c x^2\right )^3 \arctan (a x)^2 \, dx=\frac {c^3 \left (1+a^2 x^2\right )}{35 a^2}+\frac {3 c^3 \left (1+a^2 x^2\right )^2}{280 a^2}+\frac {c^3 \left (1+a^2 x^2\right )^3}{168 a^2}-\frac {4 c^3 x \arctan (a x)}{35 a}-\frac {2 c^3 x \left (1+a^2 x^2\right ) \arctan (a x)}{35 a}-\frac {3 c^3 x \left (1+a^2 x^2\right )^2 \arctan (a x)}{70 a}-\frac {c^3 x \left (1+a^2 x^2\right )^3 \arctan (a x)}{28 a}+\frac {c^3 \left (1+a^2 x^2\right )^4 \arctan (a x)^2}{8 a^2}+\frac {2 c^3 \log \left (1+a^2 x^2\right )}{35 a^2} \]

[Out]

1/35*c^3*(a^2*x^2+1)/a^2+3/280*c^3*(a^2*x^2+1)^2/a^2+1/168*c^3*(a^2*x^2+1)^3/a^2-4/35*c^3*x*arctan(a*x)/a-2/35
*c^3*x*(a^2*x^2+1)*arctan(a*x)/a-3/70*c^3*x*(a^2*x^2+1)^2*arctan(a*x)/a-1/28*c^3*x*(a^2*x^2+1)^3*arctan(a*x)/a
+1/8*c^3*(a^2*x^2+1)^4*arctan(a*x)^2/a^2+2/35*c^3*ln(a^2*x^2+1)/a^2

Rubi [A] (verified)

Time = 0.09 (sec) , antiderivative size = 200, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {5050, 4998, 4930, 266} \[ \int x \left (c+a^2 c x^2\right )^3 \arctan (a x)^2 \, dx=\frac {c^3 \left (a^2 x^2+1\right )^4 \arctan (a x)^2}{8 a^2}-\frac {c^3 x \left (a^2 x^2+1\right )^3 \arctan (a x)}{28 a}-\frac {3 c^3 x \left (a^2 x^2+1\right )^2 \arctan (a x)}{70 a}-\frac {2 c^3 x \left (a^2 x^2+1\right ) \arctan (a x)}{35 a}+\frac {c^3 \left (a^2 x^2+1\right )^3}{168 a^2}+\frac {3 c^3 \left (a^2 x^2+1\right )^2}{280 a^2}+\frac {c^3 \left (a^2 x^2+1\right )}{35 a^2}+\frac {2 c^3 \log \left (a^2 x^2+1\right )}{35 a^2}-\frac {4 c^3 x \arctan (a x)}{35 a} \]

[In]

Int[x*(c + a^2*c*x^2)^3*ArcTan[a*x]^2,x]

[Out]

(c^3*(1 + a^2*x^2))/(35*a^2) + (3*c^3*(1 + a^2*x^2)^2)/(280*a^2) + (c^3*(1 + a^2*x^2)^3)/(168*a^2) - (4*c^3*x*
ArcTan[a*x])/(35*a) - (2*c^3*x*(1 + a^2*x^2)*ArcTan[a*x])/(35*a) - (3*c^3*x*(1 + a^2*x^2)^2*ArcTan[a*x])/(70*a
) - (c^3*x*(1 + a^2*x^2)^3*ArcTan[a*x])/(28*a) + (c^3*(1 + a^2*x^2)^4*ArcTan[a*x]^2)/(8*a^2) + (2*c^3*Log[1 +
a^2*x^2])/(35*a^2)

Rule 266

Int[(x_)^(m_.)/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> Simp[Log[RemoveContent[a + b*x^n, x]]/(b*n), x] /; FreeQ
[{a, b, m, n}, x] && EqQ[m, n - 1]

Rule 4930

Int[((a_.) + ArcTan[(c_.)*(x_)^(n_.)]*(b_.))^(p_.), x_Symbol] :> Simp[x*(a + b*ArcTan[c*x^n])^p, x] - Dist[b*c
*n*p, Int[x^n*((a + b*ArcTan[c*x^n])^(p - 1)/(1 + c^2*x^(2*n))), x], x] /; FreeQ[{a, b, c, n}, x] && IGtQ[p, 0
] && (EqQ[n, 1] || EqQ[p, 1])

Rule 4998

Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))*((d_) + (e_.)*(x_)^2)^(q_.), x_Symbol] :> Simp[(-b)*((d + e*x^2)^q/(2*c
*q*(2*q + 1))), x] + (Dist[2*d*(q/(2*q + 1)), Int[(d + e*x^2)^(q - 1)*(a + b*ArcTan[c*x]), x], x] + Simp[x*(d
+ e*x^2)^q*((a + b*ArcTan[c*x])/(2*q + 1)), x]) /; FreeQ[{a, b, c, d, e}, x] && EqQ[e, c^2*d] && GtQ[q, 0]

Rule 5050

Int[((a_.) + ArcTan[(c_.)*(x_)]*(b_.))^(p_.)*(x_)*((d_) + (e_.)*(x_)^2)^(q_.), x_Symbol] :> Simp[(d + e*x^2)^(
q + 1)*((a + b*ArcTan[c*x])^p/(2*e*(q + 1))), x] - Dist[b*(p/(2*c*(q + 1))), Int[(d + e*x^2)^q*(a + b*ArcTan[c
*x])^(p - 1), x], x] /; FreeQ[{a, b, c, d, e, q}, x] && EqQ[e, c^2*d] && GtQ[p, 0] && NeQ[q, -1]

Rubi steps \begin{align*} \text {integral}& = \frac {c^3 \left (1+a^2 x^2\right )^4 \arctan (a x)^2}{8 a^2}-\frac {\int \left (c+a^2 c x^2\right )^3 \arctan (a x) \, dx}{4 a} \\ & = \frac {c^3 \left (1+a^2 x^2\right )^3}{168 a^2}-\frac {c^3 x \left (1+a^2 x^2\right )^3 \arctan (a x)}{28 a}+\frac {c^3 \left (1+a^2 x^2\right )^4 \arctan (a x)^2}{8 a^2}-\frac {(3 c) \int \left (c+a^2 c x^2\right )^2 \arctan (a x) \, dx}{14 a} \\ & = \frac {3 c^3 \left (1+a^2 x^2\right )^2}{280 a^2}+\frac {c^3 \left (1+a^2 x^2\right )^3}{168 a^2}-\frac {3 c^3 x \left (1+a^2 x^2\right )^2 \arctan (a x)}{70 a}-\frac {c^3 x \left (1+a^2 x^2\right )^3 \arctan (a x)}{28 a}+\frac {c^3 \left (1+a^2 x^2\right )^4 \arctan (a x)^2}{8 a^2}-\frac {\left (6 c^2\right ) \int \left (c+a^2 c x^2\right ) \arctan (a x) \, dx}{35 a} \\ & = \frac {c^3 \left (1+a^2 x^2\right )}{35 a^2}+\frac {3 c^3 \left (1+a^2 x^2\right )^2}{280 a^2}+\frac {c^3 \left (1+a^2 x^2\right )^3}{168 a^2}-\frac {2 c^3 x \left (1+a^2 x^2\right ) \arctan (a x)}{35 a}-\frac {3 c^3 x \left (1+a^2 x^2\right )^2 \arctan (a x)}{70 a}-\frac {c^3 x \left (1+a^2 x^2\right )^3 \arctan (a x)}{28 a}+\frac {c^3 \left (1+a^2 x^2\right )^4 \arctan (a x)^2}{8 a^2}-\frac {\left (4 c^3\right ) \int \arctan (a x) \, dx}{35 a} \\ & = \frac {c^3 \left (1+a^2 x^2\right )}{35 a^2}+\frac {3 c^3 \left (1+a^2 x^2\right )^2}{280 a^2}+\frac {c^3 \left (1+a^2 x^2\right )^3}{168 a^2}-\frac {4 c^3 x \arctan (a x)}{35 a}-\frac {2 c^3 x \left (1+a^2 x^2\right ) \arctan (a x)}{35 a}-\frac {3 c^3 x \left (1+a^2 x^2\right )^2 \arctan (a x)}{70 a}-\frac {c^3 x \left (1+a^2 x^2\right )^3 \arctan (a x)}{28 a}+\frac {c^3 \left (1+a^2 x^2\right )^4 \arctan (a x)^2}{8 a^2}+\frac {1}{35} \left (4 c^3\right ) \int \frac {x}{1+a^2 x^2} \, dx \\ & = \frac {c^3 \left (1+a^2 x^2\right )}{35 a^2}+\frac {3 c^3 \left (1+a^2 x^2\right )^2}{280 a^2}+\frac {c^3 \left (1+a^2 x^2\right )^3}{168 a^2}-\frac {4 c^3 x \arctan (a x)}{35 a}-\frac {2 c^3 x \left (1+a^2 x^2\right ) \arctan (a x)}{35 a}-\frac {3 c^3 x \left (1+a^2 x^2\right )^2 \arctan (a x)}{70 a}-\frac {c^3 x \left (1+a^2 x^2\right )^3 \arctan (a x)}{28 a}+\frac {c^3 \left (1+a^2 x^2\right )^4 \arctan (a x)^2}{8 a^2}+\frac {2 c^3 \log \left (1+a^2 x^2\right )}{35 a^2} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.05 (sec) , antiderivative size = 100, normalized size of antiderivative = 0.50 \[ \int x \left (c+a^2 c x^2\right )^3 \arctan (a x)^2 \, dx=\frac {c^3 \left (57 a^2 x^2+24 a^4 x^4+5 a^6 x^6-6 a x \left (35+35 a^2 x^2+21 a^4 x^4+5 a^6 x^6\right ) \arctan (a x)+105 \left (1+a^2 x^2\right )^4 \arctan (a x)^2+48 \log \left (1+a^2 x^2\right )\right )}{840 a^2} \]

[In]

Integrate[x*(c + a^2*c*x^2)^3*ArcTan[a*x]^2,x]

[Out]

(c^3*(57*a^2*x^2 + 24*a^4*x^4 + 5*a^6*x^6 - 6*a*x*(35 + 35*a^2*x^2 + 21*a^4*x^4 + 5*a^6*x^6)*ArcTan[a*x] + 105
*(1 + a^2*x^2)^4*ArcTan[a*x]^2 + 48*Log[1 + a^2*x^2]))/(840*a^2)

Maple [A] (verified)

Time = 1.07 (sec) , antiderivative size = 168, normalized size of antiderivative = 0.84

method result size
parts \(\frac {c^{3} \arctan \left (a x \right )^{2} a^{6} x^{8}}{8}+\frac {c^{3} \arctan \left (a x \right )^{2} a^{4} x^{6}}{2}+\frac {3 c^{3} \arctan \left (a x \right )^{2} a^{2} x^{4}}{4}+\frac {c^{3} \arctan \left (a x \right )^{2} x^{2}}{2}+\frac {c^{3} \arctan \left (a x \right )^{2}}{8 a^{2}}-\frac {c^{3} \left (\frac {\arctan \left (a x \right ) a^{7} x^{7}}{7}+\frac {3 \arctan \left (a x \right ) a^{5} x^{5}}{5}+\arctan \left (a x \right ) x^{3} a^{3}+x \arctan \left (a x \right ) a -\frac {a^{6} x^{6}}{42}-\frac {4 a^{4} x^{4}}{35}-\frac {19 a^{2} x^{2}}{70}-\frac {8 \ln \left (a^{2} x^{2}+1\right )}{35}\right )}{4 a^{2}}\) \(168\)
derivativedivides \(\frac {\frac {c^{3} \arctan \left (a x \right )^{2} a^{8} x^{8}}{8}+\frac {a^{6} c^{3} x^{6} \arctan \left (a x \right )^{2}}{2}+\frac {3 a^{4} c^{3} x^{4} \arctan \left (a x \right )^{2}}{4}+\frac {a^{2} c^{3} x^{2} \arctan \left (a x \right )^{2}}{2}+\frac {c^{3} \arctan \left (a x \right )^{2}}{8}-\frac {c^{3} \left (\frac {\arctan \left (a x \right ) a^{7} x^{7}}{7}+\frac {3 \arctan \left (a x \right ) a^{5} x^{5}}{5}+\arctan \left (a x \right ) x^{3} a^{3}+x \arctan \left (a x \right ) a -\frac {a^{6} x^{6}}{42}-\frac {4 a^{4} x^{4}}{35}-\frac {19 a^{2} x^{2}}{70}-\frac {8 \ln \left (a^{2} x^{2}+1\right )}{35}\right )}{4}}{a^{2}}\) \(169\)
default \(\frac {\frac {c^{3} \arctan \left (a x \right )^{2} a^{8} x^{8}}{8}+\frac {a^{6} c^{3} x^{6} \arctan \left (a x \right )^{2}}{2}+\frac {3 a^{4} c^{3} x^{4} \arctan \left (a x \right )^{2}}{4}+\frac {a^{2} c^{3} x^{2} \arctan \left (a x \right )^{2}}{2}+\frac {c^{3} \arctan \left (a x \right )^{2}}{8}-\frac {c^{3} \left (\frac {\arctan \left (a x \right ) a^{7} x^{7}}{7}+\frac {3 \arctan \left (a x \right ) a^{5} x^{5}}{5}+\arctan \left (a x \right ) x^{3} a^{3}+x \arctan \left (a x \right ) a -\frac {a^{6} x^{6}}{42}-\frac {4 a^{4} x^{4}}{35}-\frac {19 a^{2} x^{2}}{70}-\frac {8 \ln \left (a^{2} x^{2}+1\right )}{35}\right )}{4}}{a^{2}}\) \(169\)
parallelrisch \(\frac {105 c^{3} \arctan \left (a x \right )^{2} a^{8} x^{8}-30 c^{3} \arctan \left (a x \right ) a^{7} x^{7}+420 a^{6} c^{3} x^{6} \arctan \left (a x \right )^{2}+5 a^{6} c^{3} x^{6}-126 a^{5} c^{3} x^{5} \arctan \left (a x \right )+630 a^{4} c^{3} x^{4} \arctan \left (a x \right )^{2}+24 a^{4} c^{3} x^{4}-210 a^{3} c^{3} x^{3} \arctan \left (a x \right )+420 a^{2} c^{3} x^{2} \arctan \left (a x \right )^{2}+57 a^{2} c^{3} x^{2}-210 a \,c^{3} x \arctan \left (a x \right )+105 c^{3} \arctan \left (a x \right )^{2}+48 c^{3} \ln \left (a^{2} x^{2}+1\right )}{840 a^{2}}\) \(190\)
risch \(-\frac {c^{3} \left (a^{2} x^{2}+1\right )^{4} \ln \left (i a x +1\right )^{2}}{32 a^{2}}+\frac {c^{3} \left (35 a^{8} x^{8} \ln \left (-i a x +1\right )+10 i a^{7} x^{7}+140 a^{6} x^{6} \ln \left (-i a x +1\right )+42 i a^{5} x^{5}+210 x^{4} \ln \left (-i a x +1\right ) a^{4}+70 i a^{3} x^{3}+140 a^{2} x^{2} \ln \left (-i a x +1\right )+70 i a x +35 \ln \left (-i a x +1\right )\right ) \ln \left (i a x +1\right )}{560 a^{2}}-\frac {c^{3} a^{6} x^{8} \ln \left (-i a x +1\right )^{2}}{32}-\frac {i c^{3} a^{5} x^{7} \ln \left (-i a x +1\right )}{56}-\frac {c^{3} a^{4} x^{6} \ln \left (-i a x +1\right )^{2}}{8}-\frac {3 i c^{3} a^{3} x^{5} \ln \left (-i a x +1\right )}{40}+\frac {c^{3} a^{4} x^{6}}{168}-\frac {3 c^{3} a^{2} x^{4} \ln \left (-i a x +1\right )^{2}}{16}-\frac {i c^{3} a \,x^{3} \ln \left (-i a x +1\right )}{8}+\frac {c^{3} a^{2} x^{4}}{35}-\frac {c^{3} x^{2} \ln \left (-i a x +1\right )^{2}}{8}-\frac {i c^{3} x \ln \left (-i a x +1\right )}{8 a}+\frac {19 c^{3} x^{2}}{280}-\frac {c^{3} \ln \left (-i a x +1\right )^{2}}{32 a^{2}}+\frac {2 c^{3} \ln \left (-a^{2} x^{2}-1\right )}{35 a^{2}}\) \(378\)

[In]

int(x*(a^2*c*x^2+c)^3*arctan(a*x)^2,x,method=_RETURNVERBOSE)

[Out]

1/8*c^3*arctan(a*x)^2*a^6*x^8+1/2*c^3*arctan(a*x)^2*a^4*x^6+3/4*c^3*arctan(a*x)^2*a^2*x^4+1/2*c^3*arctan(a*x)^
2*x^2+1/8*c^3*arctan(a*x)^2/a^2-1/4*c^3/a^2*(1/7*arctan(a*x)*a^7*x^7+3/5*arctan(a*x)*a^5*x^5+arctan(a*x)*x^3*a
^3+x*arctan(a*x)*a-1/42*a^6*x^6-4/35*a^4*x^4-19/70*a^2*x^2-8/35*ln(a^2*x^2+1))

Fricas [A] (verification not implemented)

none

Time = 0.25 (sec) , antiderivative size = 156, normalized size of antiderivative = 0.78 \[ \int x \left (c+a^2 c x^2\right )^3 \arctan (a x)^2 \, dx=\frac {5 \, a^{6} c^{3} x^{6} + 24 \, a^{4} c^{3} x^{4} + 57 \, a^{2} c^{3} x^{2} + 48 \, c^{3} \log \left (a^{2} x^{2} + 1\right ) + 105 \, {\left (a^{8} c^{3} x^{8} + 4 \, a^{6} c^{3} x^{6} + 6 \, a^{4} c^{3} x^{4} + 4 \, a^{2} c^{3} x^{2} + c^{3}\right )} \arctan \left (a x\right )^{2} - 6 \, {\left (5 \, a^{7} c^{3} x^{7} + 21 \, a^{5} c^{3} x^{5} + 35 \, a^{3} c^{3} x^{3} + 35 \, a c^{3} x\right )} \arctan \left (a x\right )}{840 \, a^{2}} \]

[In]

integrate(x*(a^2*c*x^2+c)^3*arctan(a*x)^2,x, algorithm="fricas")

[Out]

1/840*(5*a^6*c^3*x^6 + 24*a^4*c^3*x^4 + 57*a^2*c^3*x^2 + 48*c^3*log(a^2*x^2 + 1) + 105*(a^8*c^3*x^8 + 4*a^6*c^
3*x^6 + 6*a^4*c^3*x^4 + 4*a^2*c^3*x^2 + c^3)*arctan(a*x)^2 - 6*(5*a^7*c^3*x^7 + 21*a^5*c^3*x^5 + 35*a^3*c^3*x^
3 + 35*a*c^3*x)*arctan(a*x))/a^2

Sympy [A] (verification not implemented)

Time = 0.58 (sec) , antiderivative size = 207, normalized size of antiderivative = 1.04 \[ \int x \left (c+a^2 c x^2\right )^3 \arctan (a x)^2 \, dx=\begin {cases} \frac {a^{6} c^{3} x^{8} \operatorname {atan}^{2}{\left (a x \right )}}{8} - \frac {a^{5} c^{3} x^{7} \operatorname {atan}{\left (a x \right )}}{28} + \frac {a^{4} c^{3} x^{6} \operatorname {atan}^{2}{\left (a x \right )}}{2} + \frac {a^{4} c^{3} x^{6}}{168} - \frac {3 a^{3} c^{3} x^{5} \operatorname {atan}{\left (a x \right )}}{20} + \frac {3 a^{2} c^{3} x^{4} \operatorname {atan}^{2}{\left (a x \right )}}{4} + \frac {a^{2} c^{3} x^{4}}{35} - \frac {a c^{3} x^{3} \operatorname {atan}{\left (a x \right )}}{4} + \frac {c^{3} x^{2} \operatorname {atan}^{2}{\left (a x \right )}}{2} + \frac {19 c^{3} x^{2}}{280} - \frac {c^{3} x \operatorname {atan}{\left (a x \right )}}{4 a} + \frac {2 c^{3} \log {\left (x^{2} + \frac {1}{a^{2}} \right )}}{35 a^{2}} + \frac {c^{3} \operatorname {atan}^{2}{\left (a x \right )}}{8 a^{2}} & \text {for}\: a \neq 0 \\0 & \text {otherwise} \end {cases} \]

[In]

integrate(x*(a**2*c*x**2+c)**3*atan(a*x)**2,x)

[Out]

Piecewise((a**6*c**3*x**8*atan(a*x)**2/8 - a**5*c**3*x**7*atan(a*x)/28 + a**4*c**3*x**6*atan(a*x)**2/2 + a**4*
c**3*x**6/168 - 3*a**3*c**3*x**5*atan(a*x)/20 + 3*a**2*c**3*x**4*atan(a*x)**2/4 + a**2*c**3*x**4/35 - a*c**3*x
**3*atan(a*x)/4 + c**3*x**2*atan(a*x)**2/2 + 19*c**3*x**2/280 - c**3*x*atan(a*x)/(4*a) + 2*c**3*log(x**2 + a**
(-2))/(35*a**2) + c**3*atan(a*x)**2/(8*a**2), Ne(a, 0)), (0, True))

Maxima [A] (verification not implemented)

none

Time = 0.19 (sec) , antiderivative size = 133, normalized size of antiderivative = 0.66 \[ \int x \left (c+a^2 c x^2\right )^3 \arctan (a x)^2 \, dx=\frac {{\left (a^{2} c x^{2} + c\right )}^{4} \arctan \left (a x\right )^{2}}{8 \, a^{2} c} + \frac {{\left (5 \, a^{4} c^{4} x^{6} + 24 \, a^{2} c^{4} x^{4} + 57 \, c^{4} x^{2} + \frac {48 \, c^{4} \log \left (a^{2} x^{2} + 1\right )}{a^{2}}\right )} a - 6 \, {\left (5 \, a^{6} c^{4} x^{7} + 21 \, a^{4} c^{4} x^{5} + 35 \, a^{2} c^{4} x^{3} + 35 \, c^{4} x\right )} \arctan \left (a x\right )}{840 \, a c} \]

[In]

integrate(x*(a^2*c*x^2+c)^3*arctan(a*x)^2,x, algorithm="maxima")

[Out]

1/8*(a^2*c*x^2 + c)^4*arctan(a*x)^2/(a^2*c) + 1/840*((5*a^4*c^4*x^6 + 24*a^2*c^4*x^4 + 57*c^4*x^2 + 48*c^4*log
(a^2*x^2 + 1)/a^2)*a - 6*(5*a^6*c^4*x^7 + 21*a^4*c^4*x^5 + 35*a^2*c^4*x^3 + 35*c^4*x)*arctan(a*x))/(a*c)

Giac [F]

\[ \int x \left (c+a^2 c x^2\right )^3 \arctan (a x)^2 \, dx=\int { {\left (a^{2} c x^{2} + c\right )}^{3} x \arctan \left (a x\right )^{2} \,d x } \]

[In]

integrate(x*(a^2*c*x^2+c)^3*arctan(a*x)^2,x, algorithm="giac")

[Out]

sage0*x

Mupad [B] (verification not implemented)

Time = 0.52 (sec) , antiderivative size = 156, normalized size of antiderivative = 0.78 \[ \int x \left (c+a^2 c x^2\right )^3 \arctan (a x)^2 \, dx={\mathrm {atan}\left (a\,x\right )}^2\,\left (\frac {c^3}{8\,a^2}+\frac {c^3\,x^2}{2}+\frac {3\,a^2\,c^3\,x^4}{4}+\frac {a^4\,c^3\,x^6}{2}+\frac {a^6\,c^3\,x^8}{8}\right )+\frac {19\,c^3\,x^2}{280}-a^2\,\mathrm {atan}\left (a\,x\right )\,\left (\frac {c^3\,x}{4\,a^3}+\frac {3\,a\,c^3\,x^5}{20}+\frac {c^3\,x^3}{4\,a}+\frac {a^3\,c^3\,x^7}{28}\right )+\frac {2\,c^3\,\ln \left (a^2\,x^2+1\right )}{35\,a^2}+\frac {a^2\,c^3\,x^4}{35}+\frac {a^4\,c^3\,x^6}{168} \]

[In]

int(x*atan(a*x)^2*(c + a^2*c*x^2)^3,x)

[Out]

atan(a*x)^2*(c^3/(8*a^2) + (c^3*x^2)/2 + (3*a^2*c^3*x^4)/4 + (a^4*c^3*x^6)/2 + (a^6*c^3*x^8)/8) + (19*c^3*x^2)
/280 - a^2*atan(a*x)*((c^3*x)/(4*a^3) + (3*a*c^3*x^5)/20 + (c^3*x^3)/(4*a) + (a^3*c^3*x^7)/28) + (2*c^3*log(a^
2*x^2 + 1))/(35*a^2) + (a^2*c^3*x^4)/35 + (a^4*c^3*x^6)/168